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Exact Answer
9/32 + 2/5 = 109/160
Simplified Fraction
109/160
Mixed Number
Proper (109/160)
Decimal Value
0.68125
Percentage
68.125%

Step-by-Step Solution: 9/32 + 2/5

Step 1

Find the Least Common Denominator (LCD)

The denominators 32 and 5 are coprime (they share no common factors other than 1). Therefore, their Least Common Denominator (LCD) is simply their direct product: 32 × 5 = 160.
LCD(32, 5) = 160
Step 2

Convert to Equivalent Fractions with Common Denominator 160

Multiply the numerator and denominator of 9/32 by 5, and multiply the numerator and denominator of 2/5 by 32 so both fractions share the common base 160.
9 × 5/32 × 5 = 45/160   and   2 × 32/5 × 32 = 64/160
Step 3

Add the Numerators

Now add the numerators (45 + 64 = 109) and keep the common denominator 160 unchanged.
45 + 64/160 = 109/160
Step 4

Check if the Fraction Can Be Simplified

The Greatest Common Divisor (GCD) of 109 and 160 is 1, confirming that 109/160 cannot be reduced further—it is already in its simplest irreducible form.
109/160
Step 5

Decimal & Percentage Representation

Dividing the numerator 109 by denominator 160 yields an exact terminating decimal of 0.68125 (or 68.125%).
109 ÷ 160 = 0.68125 (68.125%)

Visual Representation

The diagram below illustrates 9/32 plus 2/5 visually:

9/329 of 32 parts shadedValue: 0.2813 (28.1%)
+
2/5⅕⅕⅕⅕⅕2 of 5 parts shadedValue: 0.4 (40%)
=
Result: 109/160109 of 160 parts shadedValue: 0.6813 (68.1%)

Summary & Alternative Representations

Property / FormatValue
Lowest Terms Fraction109/160
Mixed Number Form109/160
Decimal Form0.68125
Percentage68.125%

Frequently Asked Questions

What is 9/32 plus 2/5 as a fraction?

9/32 + 2/5 in simplest fraction form is 109/160.

What is 9/32 plus 2/5 as a decimal?

9/32 + 2/5 converted to a decimal is 0.68125.

What is 9/32 plus 2/5 as a percentage?

9/32 + 2/5 expressed as a percentage is 68.125%.

Does 9/32 plus 2/5 result in a terminating or repeating decimal?

It results in an exact terminating decimal (0.68125) because the denominator in simplest terms contains only prime factors 2 and/or 5.