What is P(6, 2)? — 6 Permute 2
There are 30 possible permutations of 2 items chosen from 6 (nPr = 30), and 15 combinations (nCr = 15).
Exact Answer
P(6, 2) = 30
Combinations C(n,r)
15
Permutations P(n,r)
30
n! (6!)
720
r! (2!)
2
Step-by-Step Solution: P(6, 2) = 30
Step 1
Use the Permutations Formula nPr = n! / (n − r)!
Substitute n = 6 and r = 2: 6! = 720, (6−2)! = 24.
P(6, 2) = 30
Summary & Alternative Representations
| Property / Format | Value |
|---|---|
| Combinations C(n,r) | 15 |
| Permutations P(n,r) | 30 |
| n! (6!) | 720 |
| r! (2!) | 2 |
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Frequently Asked Questions
What is the difference between C(6,2) and P(6,2)?
Combinations C(6,2) = 15 (order does not matter), whereas Permutations P(6,2) = 30 (order matters).